\lim_{x\to0} {\tan^{3}3x}/{5x^{3}}=

AP ICET 2016 Paper

Question : 111 of 200

Marks: +1, -0

\lim↙{x→0}\;\;{\tan^{3}3x}/{5x^{3}}=

Solution:

\lim↙{x→0}{\tan^{3}3x}/{5x^{3}}

={1}/{5}\lim↙{3x→0}{\tan^{3}3x}/{(3x)^{3}}×(3)^{3}

={27}/{5}[\lim↙{3x→0}{\tan3x}/{3x}=1]

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