AP ICET 2016 Paper

© examsiri.com

Question : 110 of 200

Marks: +1, -0

A sector area of a circle of radius 14 cm is

154/3cm^2

Then the angle of the sector (in radians) is

$π/3$
$π/6$
$π/4$
$π/12$

Solution:

Area of a sector of a circle

=(θ/{2π})πr^2

where θ is in radian.

⇒θ/2r^2=A

⇒θ={2A}/{r^{2}}={2×154}/{14×14×3}={22}/{7×6}={π}/{6}

radian
Aliter

A=({θ°}/{360°})π^{2}⇒{θ°=360×A}/{πr^{2}}

⇒θ°={360×154}/{{22}/{7}×14×14×3}=30°={π}/{6}

radian

© examsiri.com

Go to Question:

Prev Question

Next Question