If \sqrt{19-4\sqrt{x}=\sqrt{12}-\sqrt{7} then x-1=

AP ICET 2015 Paper

Question : 80 of 200

Marks: +1, -0

√{19-4√{x}}=√{12}-√{7}

then

x-1=

Solution:

Given :

√{19-4√{x}}=√{12}-√{7}

Squaring both sides,

19-4√{x}=12+7-2√{12×7}

⇒-4√{x}=-2√{84}=-4√{21}

⇒x=21

∴x-1=20

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