If {\A}+ {\B}+ {\C}+ {\D}=2 \pi, then \sin {\A}+ \sin {\B}+ \sin {\C}+ \sin {\D}= [AP EAPCET 26 May 2025 S1]

Correct Answer is : 4sin(A+B2)sin(A+C2)sin(A+D2)

4 \sin (\frac{A+B}{4}) \sin (\frac{A+C}{4}) \sin (\frac{A+D}{4})

4 \sin ( { {\A}+ {\B}}/{2}) \cos ( { {\A}+ {\C}}/{4}) \cos ( { {\A}+ {\D}}/{4})

4 \sin ( { {\A}+ {\B}}/{2}) \sin ( { {\A}+ {\C}}/{2}) \sin ( { {\A}+ {\D}}/{2})

4 \sin ( { {\A}+ {\B}}/{2}) \sin ( { {\A}+ {\C}}/{4}) \sin ( { {\A}+ {\D}}/{4})

AP EAPCET 26 May 2025 Shift 1 Paper

Section: Mathematics

Question : 22 of 160

Marks: +1, -0

If A+B+C+D=2π, then sin‌A+sin‌B+sin‌C+sin‌D=

[AP EAPCET 26 May 2025 S1]

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