If \tan (\frac{\pi}{4}+\alpha) =\tan ^3 (\frac{\pi}{4}+\beta), then \tan (\alpha+\beta) \cot (\alpha-\beta)= [AP EAPCET 26 May 2025 S1]

Correct Answer is : 2( sec22β+tan22β)

\sec ^2 2 \beta+\tan ^2 2 \beta

{\cosec}^2 2 \beta+\cot ^2 2 \beta

2 ( \sec ^2 2 \beta+\tan ^2 2 \beta)

4 ( \sec ^2 2 \beta+\tan ^2 2 \beta)

AP EAPCET 26 May 2025 Shift 1 Paper

Section: Mathematics

Question : 21 of 160

Marks: +1, -0

If tan(‌

+α)=tan3(‌

+β), then tan(α+β)‌cot(α−β)=

[AP EAPCET 26 May 2025 S1]

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