\int \frac{1+x \cos x}{x [1-x^2 (e^{ \sin x}) ^2] } \dx=

Correct Answer is : 12log|(xesinx)2(xesinx)2−1|+c

\frac{1}{2} \log {| { (x e^{ \sin x}) ^2}/{ ( {\xe}^{ \sin x}) ^2+1} |}+ {\c}

-\frac{1}{2} \log {| { ( {\xe}^{ \sin {\x}}) ^2}/{ ( {\xe}^{ \sin x}) ^2+1} |}+ {\c}

\frac{1}{2} \log {| { (x e^{ \sin x}) ^2}/{ (x e^{ \sin x}) ^2-1} |}+c

-\frac{1}{2} \log {| { ( {\xe}^{ \sin {\x}}) ^2}/{ ( {\xe}^{ \sin {\x}}) ^2-1} |}+ {\c}

AP EAPCET 19th May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 70 of 160

Marks: +1, -0

∫‌

1+x‌cos‌x

x[1−x2(esin‌x)2]

‌dx=

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