If f(x)=\frac{x}{ (1+n x^n) ^{1 \/ n}} for n \geq 2, then \int x^{n-2} f(x) \dx=

Correct Answer is : 1n(n−1)(1+nxn)1−1n+C

\frac{1}{n(n-1)} (1+n x^n) ^{1-\frac{1}{n}}+C

\frac{1}{n-1} (1+n x^n) ^{1-\frac{1}{n}}+C

\frac{1}{n(n-1)} (1+n x^n) ^{1+\frac{1}{n}}+C

\frac{1}{n+1} (1+n x^n) ^{1+\frac{1}{n}}+C

AP EAPCET 19th May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 69 of 160

Marks: +1, -0

If f(x)=‌

(1+nxn)1∕n

for n≥2, then ∫xn−2f(x)‌dx=

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