AP EAPCET 19-Aug-2021 Shift 2 Paper

Given, range of mass is from m1 to m2 i.e. 0 to 15‌kg
Length of spring, x=0.25m
Time period of oscillation, T=

2π

5

s
Let mass of body suspended =m
Spring constant =k
Acceleration due to gravity g=10ms−2
Since, T=2π.√

m

k

...(i)
and F=mg=kx
⇒k=

mg

x

=

15×10

0.25

N∕m
Substituting in Eq. (i), we get
T=2π√

m×25

15×10×100

⇒(

2π

5

)2=(2π)2(

m

15×40

)
⇒

4π2

25

=

4π2m

15×40

⇒m=24‌kg