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Question : 75 of 160
Marks:
+1,
-0
Solution:
‌ Let ‌I‌=‌‌dx ‌=‌‌dx‌ =‌‌dx Let
ex=t ⇒‌‌ex‌dx=dt When
x⟶log‌4,t⟶4 x‌⟶log‌5,t⟶5 I‌=‌‌dt ‌=‌−‌ [ ∵ by partial fraction]
‌=[4‌log|t−3|−3‌log|t−2|]45 ‌=[log|‌.]45 ‌=log‌−log‌=log‌×23 ‌=log(‌)=log(‌)
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