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Question : 74 of 160
Marks:
+1,
-0
Solution:
‌x4[]‌‌‌[∵‌=0]‌‌‌[‌]‌=‌‌dx‌‌‌ Let ‌x=tan‌θ‌dx= sec2θdθ‌x⟶0,θ⟶0‌ and ‌‌x⟶1,θ⟶‌‌‌=‌× sec2θdθ‌‌=‌dθ‌‌=cos3θdθ‌‌=‌‌(cos‌3‌θ+3‌cos‌θ)dθ‌‌=‌[‌+3sin‌θ]0π∕4‌‌=‌[‌sin‌(π−‌)+3sin‌‌]‌‌=‌[‌×‌+‌]‌‌=‌⇒‌=‌
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