\int(1+x) \log (1+x^{2}) d x=(x+\frac{x^{2}}{2}+\frac{1}{2}) \log (1+x^{2})+g(x)+C, then g(x)=

Correct Answer is : −2x−x22+2tan−1x

-2 x-\frac{x^{2}}{2}+2 \tan ^{-1} x

2 \tan ^{-1} x+\frac{x^{2}}{2}+\frac{x^{3}}{3}

2 \tan ^{-1} x-\frac{x^{2}}{2}+3 x

2 \tan ^{-1} x+3 x+\frac{x^{3}}{2}

AP EAPCET 08-Jul-2022 Shift 1 Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

∫(1+x)‌log(1+x2)‌d‌x=(x+‌

+‌

)‌log(1+x2)+g(x)+C, then g(x)=

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