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Question : 72 of 160
Marks:
+1,
-0
Solution:
Let
I=∫dx I=2‌∫| cos‌ |
| sin(x−)‌cos‌x |
dx=2‌∫| cos(x−−x) |
| sin(x−)‌cos‌x |
‌dx =2‌∫[| cos(x−)‌cos‌x |
| sin(x−)‌cos‌x |
+| sin(x−)‌sin‌x |
| sin(x−)‌cos‌x |
]dx =2‌∫[cot(x−)+tan‌x]dx =2[log‌|sin(x−)|−log|cos‌x|]+C =2[log∣−]+C =2[log‌||]+C
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