A particle is moving along {x}-axis with velocity {v}= {e}^{- {\beta x}}. At time {t}=0, the particle is

Correct Answer is : 1βlog[1+βt]

\frac{1}{\beta} e^{(1-\beta t)}

\frac{1}{\beta} \log [1-\beta t]

\frac{1}{\beta} \log [1+\beta t]

AP EAPCET 07-Jul-2022 Shift 1 Paper

Section: Physics

Question : 84 of 160

Marks: +1, -0

A particle is moving along x-axis with velocity v=e−βx. At time t=0, the particle is

Go to Question:

Prev Question

Next Question