AP EAPCET 07-Jul-2022 Shift 1 Paper
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Question : 83 of 160
Marks:
+1,
-0
A ball is projected from ground into the air. At the height of 5 m , its velocity is
= ( 5
+ 5
) m s − 1 . The maximum height reached by the ball is (Acceleration due to gravity = 10 m s − 2 )
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