AP EAPCET 06-Jul-2022 Shift 2 Paper

Given, V of water =1L=1000‌mL
Density of water =1.0gcm−3
To find, mass of hydrogen in water (in g)
d=‌

m

V

(for water)
⇒1=‌

m

1000

∴‌m=1000g
Molecular mass of H2O=(2×1)+16=18
∵18g of water has =2g hydrogen
∴1000g of water has =‌

2

18

×1000g of hydrogen
=111.11g of hydrogen
=1.11×102g