1L of 0.02M aqueous HCl is mixed with 1L of 0.01M aqueous H2SO4 solution. Assuming complete dissociation and no change in the volume upon mixing, the pH of resultant solution is (log102=0.3)
Given HCl‌1‌L‌0.02‌M H2SO41L0.01M Moles of H+from HCl=1×0.02=0.02 Moles of H+from H2SO4=1×0.01×2=0.02 Total moles in mixture =0.02+0.02=0.04 [H+]‌=‌