AP EAPCET 05-Jul-2022 Shift 1 Paper

Initial speed of body on the horizontal rough surfaces, u=10ms−1
Final velocity, v=4ms−1 and t=2 s.
If a be the retardation due to friction, then by using equation,
v‌=u−at
⇒‌‌4=10−a×2
⇒‌‌2a=6⇒a=3ms−2
According to given situation, friction force =ma
‌⇒‌‌µkmg=ma
‌⇒‌‌µk=‌

a

g

=‌

3

10

=0.3