If two vectors \overrightarrow{A} and \overrightarrow{ {B} are mutually perpendicular, then the component of \overrightarrow{ {A} \cdot \overrightarrow{ {B} along the direction of \overrightarrow{ {A}+\overrightarrow{ {B} is

Correct Answer is : |→A|2−|→B|2√|→A|2+|→B|2

\sqrt\overrightarrow{|{A}|^{2}+|\overrightarrow{B}|^{2}}

\sqrt\overrightarrow{|{A}|^{2}-|\overrightarrow{B}|^{2}}

\overrightarrow{{{ |{A}|^{2}-|\overrightarrow{ {B}|^{2}}}/\sqrt\overrightarrow{|{ {A}|^{2}+|\overrightarrow{ {B}|^{2}}}

\overrightarrow{|{A}|^{2}+|\overrightarrow{B}|^{2}}/\sqrt\overrightarrow{|{A}|^{2}-|\overrightarrow{B}|^{2}}}

AP EAPCET 05-Jul-2022 Shift 1 Paper

Section: Physics

Question : 85 of 160

Marks: +1, -0

If two vectors

→

and

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are mutually perpendicular, then the component of

→

⋅

→

along the direction of

→

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