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Question : 80 of 160
Marks:
+1,
-0
Solution:
y=Aex+Be−2x On differentiating w.r.t.
x, we get
‌=Aex−2Be−2x....(i)
Again on differentiating w.r.t.
x, we get
‌=Aex+4Be−2x.....(ii)
Adding Eqs. (ii) and (iii), we get
‌‌+‌=2Aex+2Be−2x=2y⇒‌+‌−2y=0
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