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Question : 31 of 160
Marks:
+1,
-0
Solution:
The normal to the plane
P1 is calculated as,
n1=|| =i The normal to the plane
P2 is calculated as,
n2=|| =−9k So,
n1×n2=i×(−9k) =−9(i×k) =−9j Therefore, the angle between
−9j and
i+j+k is
cos‌θ±() =± θ=cos−1(±)
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