AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper

Consider the figure shown below.The points L,M,N divides the line BC,CA,AB in the ration 1: 2,2: 3 and 3: 5
So,
L=

2b+c

3

M=

2a+3c

5

N=

3b+5a

8

K=

5b+3a

8

So,
AL=

2b+c

3

−a
=

2b+c−3a

3

And,
BM=

2a+3c

5

−b
=

2a+3c−5b

5

And,
CN=

3b+5a

8

−c
=

3b+5a−8c

8

And,
CK=

5b+3a

8

−c
=

5b+3a−8c

8

Therefore,
|

AL+BM+CN

CK

| =|

5b+3a−8c

15(5b+3a−8c)

|
=

1

15