AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

Section: Mathematics

Question : 51 of 160

Marks: +1, -0

A circle S of radius 2 units lies in the first quadrant and touches both the coordinate axes. The equation of the circle with centre at (6, 5) and touching the circle S externally is

x2+y2 - 12x - 10y + 12 = 0
x2+y2 - 12x - 10y - 20 = 0
x2+y2 - 12x - 10y + 25 = 0
x2+y2 - 12x - 10y + 52 = 0

Validate

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