AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

The equation of the polar of point P(2,3) with respect toequation of circle x2+y2−2x−2y+1=0 is,
T=0
This implies,
2x+3y−(x+2)−(y+3)+1=0
x+2y−4=0 ....(I)
The equation of the line joining point P(2,3) and center ofcircle C(1,1) is,
y−1=

2

1

(x−1)
2x−y−1=0
The equation of polar of point Q(

6

5

,

7

5

) with respect to circle is,

6

5

x+

7

5

y−(x+

6

5

)−(y+

7

5

) +1=0
x+2y−8=0 ....(II)
So, the required distance from equation (I) and (II) is,

4

√1+4

=

4

√5