AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

The oxidation state of sulphur in H2S2O8 is,
x+2(−2)+1(−1)+1(−1)‌‌=0
x‌‌=+6
The oxidation state of sulphur in H2SO5 is,
x+2(−2)+1(−1)+1(−1)=0
x=+6
The oxidation state of sulphur in H2SO3 is,
x+2(−1)+1(−2)‌‌=0
x‌‌=+4
The oxidation state of sulphur in H2SO4 is,
x+2(−1)+1(−2)=0
x=+4
The oxidation state of sulphur in H2S2O7 is,
x+2(−2)+1(−1)+1(−1)=0
x=+6
The oxidation state of sulphur in SO2Cl2 is,
x+2(−2)+1(−1)+1(−1)=0
x=+6
The oxidation state of sulphur in SOCl2 is,
x+1(−2)+2(−1)=0
x=+4
Thus, the compound having +6O.S is 4