AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

The average kinetic energy is given as,
E=‌

3

2

RT
Substitute the given value in above expression.
4×103J∕mol‌‌=‌

3

2

×8.314J∕Kmol×T
T‌‌=320K
The expression for root mea square velocity is given as,
vrms=√‌

3RT

M

Substitute the value in above expression.
5×102

m

s

‌‌=√‌

3×8.314J∕kmol×320K

M

M≈32g∕mol