AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Mathematics

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Question : 25 of 160

Marks: +1, -0

If x = −

1

2

, sinh−1x+cosech−1x =

loge(
7−3√5
2
)
loge(
3+√5
2
)
loge [
(√5−1)(2+√3)
2
]
loge [
(√5+1)(2+√3)
2
]

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