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Question : 24 of 160
Marks:
+1,
-0
Solution:
Given expression is solved as,
tan−12+cot−1(−3)+cot−1() +tan−1(−) =tan−1(2)−tan−1()+π−cot−1(3) +cot−1() =tan−1(2)−tan−1( )+π−tan−1() +tan−1(3) =tan−1(2−1+2× )+π +tan−1() =π+tan−1( )+tan−1() =π+=
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