If \alpha,\beta,\gamma are any three angles, then \cos\alpha+ \cos\beta -\cos\gamma -\cos( \alpha+ \beta+ \gamma) =

Correct Answer is : 4cosα+β2sinβ+γ2sinγ+α2

4\cos{\alpha+\beta}/2\cos{\beta+\gamma}/2\cos{\gamma+\alpha}/2

4\cos{\alpha+\beta}/2\sin{\beta+\gamma}/2\sin{\gamma+\alpha}/2

4\cos{\alpha+\beta}/2\sin{\beta-\gamma}/2\sin{\gamma-\alpha}/2

4\sin{\alpha+\beta}/2\cos{\beta+\gamma}/2\cos{\gamma+\alpha}/2

AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper

Section: Mathematics

Question : 22 of 160

Marks: +1, -0

If α,β,γ are any three angles, then cos‌α+cos‌β−cos‌γ−cos(α+β+γ)=

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