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Question : 21 of 160
Marks:
+1,
-0
Solution:
Solve the given expression,
=[(cos2252°−sin2126°)(cos‌252°+sin‌126°) (sin2126°+sin2186°+sin266°)] =[[−] [| 1−cos‌252°+cos‌372°+1−cos‌132° |
| 2 |
]]=[(cos‌504°+cos‌252°) (3−cos‌252°−2‌cos‌252°‌cos‌120°)]=‌cos‌18°(−sin‌36°)=−
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