The energy of a photon is equal to the kinetic energy of a proton. If \lambda_1 is the de Broglie wavelength of a proton, \lambda_2 the wavelength associated with the photon, and if the energy for the photon is E, then (\frac{\lambda _1}{\lambda _2}) is proportional to

AP EAMCET Engineering 2014 Code A Solved Paper

Question : 115 of 160

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The energy of a photon is equal to the kinetic energy of a proton. If λ1 is the de Broglie wavelength of a proton, λ2 the wavelength associated with the photon, and if the energy for the photon is E, then (

λ1

λ2

) is proportional to

E‌
1
2
E2
E
E4

Validate

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