The electric field for an electromagnetic wave in free space is, E^{-}=i^{-}30 \cos(kz-5\times10^8 t) where magnitude of E is in V/m. The magnitude of wave vector, k is (velocity of em wave in free space= 3\times10^8m/s)

Correct Answer is : 1.66 radm−1

AP EAMCET Engineering 2014 Code A Solved Paper

Question : 114 of 160

Marks: +1, -0

The electric field for an electromagnetic wave in free space is,

−

30cos(kz−5×108 t) where magnitude of E is in V/m. The magnitude of wave vector, k is (velocity of em wave in free space= 3×108m/s)

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