AMU Engineering 2017 solved paper Solved Paper

Wavelength of Balmer series is given by
=

1

λ

=RH[

1

22

−

1

ni2

]
where, ni=3,4,5,.........∞
When transition of electron takes place from ni=3 to nf=2, wavelength of emitted photon is maximum, given by

1

λmax

=RH[

1

22

−

1

32

] or λmax=6563Å
When transition of electron takes place from ni=∞ to nf=2 wavelength of emitted photon is minimum, given by

1

λmin

=RH[

1

22

−

1

∞2

] or λmin=3646Å
The range of the wavelength thus calculated is equivalent to the wavelength range at visible region of spectrum.
∴ Balmer series lie in the visible region of electromagnetic spectrum.