AMU Engineering 2017 solved paper Solved Paper

As we know that,
density of the nucleus =

mass of nucleus

volume of nucleus

Mass of the nucleus =A×1.66×10−27kg
where A is the mass number of nucleus. Volume of the nucleus =

4

3

πR3=

4

3

π(R0A1∕3)3
Thus, density =

A×1.66×10−27

( 4 3 πR03)A

=

1.66×10−27

( 4 3 πR03)

which shows that the density is independent of mass number A. Using, R0=1.2×10−15m, we get density =2.99×1017kgm−3