AIPMT 2010 Physics and Chemistry Paper

Molecules having the same number of hybrid orbitals, have same hybridisation and number of hybrid orbitals,
H=‌

1

2

[V+X−C+A]
where, V= no. of valence electrons of central atom
X= no. monovalent atoms
C= charge on cation
A= Charge on anion.
(1) ln‌SF4, H=‌

1

2

[6+4−0+0)=5
(2) ln‌l3 H=‌

1

2

[7+2+1]=5
(3) ln‌SbCl52−,H=‌

1

2

[5+5+2)=6
(4) ln‌PCl5, H=‌

1

2

[5+5+0−0]=5
Since, only SbCl52− has different number of hybrid orbitals (ie,6) from the other given species, its hybrisation is different from the others, ie, sp3d2. (The hybridsation of other species is sp3d ).