AIPMT 2008 Physics and Chemistry Paper

pH=−log10[H+]
[H+]=10−pH
[H+] of solution 1=10−3
[H+] of solution 2=10−4
[H+] of solution 3=10−5
The volume taken in each case is 1L
=10−3(1+1×10−1+1×10−2.
=10−3(‌

1

1

+‌

1

10

+‌

1

100

)
=10−3(‌

111

100

)=1.11×10−3
Therefore, H+ion concentration in mixture of equal volume of these acid solutions
=‌

1.11×10−3

3

=3.7×10−4M