AIIMS 2013 Physics Question Paper for free online practice with solutions

The transition equation for Lyman series is given by

1

λ

=R(

1

12

−

1

n2

)
for largest wavelength, n=2.
∴

1

λmax

=R(

1

12

−

1

22

)
The transition equation for Balmer series is given by

1

λ

=R(

1

22

−

1

n2

)
for largest wavelength, n=3

1

λmax

=R(

1

22

−

1

32

)
Therefore,

λLmax

λBmax

=

( 1 22 − 1 32 )

( 1 12 − 1 22 )

=

5 36

3 4

=

5

27