AIIMS 2013 Physics Question Paper for free online practice with solutions

Heat required to melt 1 g of ice at 0°C to water at 0°C = 1×80 cal.
Heat required to raise temperature of 1 g of water from 0°C to 100°C = 1×1×100=100 cal.
total heat required for maximum temperature of 100°C = 80+100=180 cal.
As one gram of steam gives 540 cal of heat when it is converted to water at 100°C, therefore, temperature of the mixture = 100°C.