For x \in (0, \frac{5 \pi}{2}), define f(x)=\int_{0}^{x} \sqrt{t} \sin t \dt. Then f has [AIEEE 2011]

Correct Answer is : local maximum at π and local minimum at 2π

local minimum at \pi and local maximum at 2 \pi

local maximum at \pi and local minimum at 2 \pi

AIEEE 2011 Solved Paper

Section: Mathematics

Question : 73 of 91

Marks: +1, -0

For x∈(0,‌

5π

), define f(x)=

∫

√tsin‌t‌dt. Then f has

[AIEEE 2011]

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