\frac{d^2 x}{d y^2} equals: [AIEEE 2011]

Correct Answer is : −(d2ydx2)(dydx)−3

- (\frac{d^2 y}{d x^2}) ^{-1} (\frac{d y}{d x}) ^{-3}

(\frac{d^2 y}{d x^2}) (\frac{d y}{d x}) ^{-2}

- (\frac{d^2 y}{d x^2}) (\frac{d y}{d x}) ^{-3}

AIEEE 2011 Solved Paper

Section: Mathematics

Question : 72 of 91

Marks: +1, -0

‌

d2x

dy2

equals:

[AIEEE 2011]

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