\int_{0}^{\pi} x f( \sin x) \dx is equal to [AIEEE 2006]

Correct Answer is : ππ/2∫0f(cosx)dx

\pi \int_{0}^{\pi} f(\cos x) \dx

\pi \int_{0}^{\pi} f( \sin x) \dx

\frac{\pi}{2} \int_{0}^{\pi {/}2} f( \sin x) \dx

\pi \int_{0}^{\pi {/} 2} f(\cos x) \dx

AIEEE 2006 Solved Paper

Section: Mathematics

Question : 134 of 143

Marks: +1, -0

∫

xf(sin‌x)‌dx is equal to

[AIEEE 2006]

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