AIEEE 2002 Math Solved Paper

Note : For a number to be divisible by 3 , the sum of digits should be divisible by 3 .
Here given numbers are 0,1,2,3,4 and 5. Out of those 6 numbers possible sets of 5 numbers are (1,2,3,4,5) and (0,1,2,4,5) whose sum are divisible by 3.
Set 1 : Set is =(1,2,3,4,5). Sum of digits =1+2+3+4+5=15 (Divisible by 3)
Five digit numberSo total no of arrangement =1×2×3×4×5=5 !
Set 2 : Set is =(0,1,2,4,5). Sum of digits =0+1+2+4+5=12 (Divisible by 3 )
Five digit numberSo total no of arrangement =4×4×3×2×1=4.4 !
∴ Total arrangement =5!+4.4!=216