AIEEE 2002 Math Solved Paper

There are 3 possible ways that we can make number greater than 1000 but less than 4000 using the digits 0,1,2,3,4 where repetition is allowed
Case 1 : First digit is 1=1
Possible numbers starting with 1=1×5×5×5=125
But this includes 1000 also which does not satisfy the given condition of being greater than 1000. Hence there will be 124 numbers having 1 in the first place.
Case 2 : First digit is 2=2
Possible numbers starting with 2=1×5×5×5=125
Case 3: First digit is 3=3
Possible numbers starting with 3=1×5×5×5=125
Total possible numbers =124+125+125=374