AFCAT I 23 Jan 2025 Shift 1 Paper

P(A)= Favorable outcomes/Total number of outcomes
Calculation:
According to the question
Total number of possible outcomes =(6×6)=36
Favorable outcomes =(1,6),(2,5),(3,4),(6,1),(5,2),(4,3),(5,6),(6,5)
P(A)= Favorable outcomes/Total number of outcomes
⇒P(A)=(8∕36)
⇒ 2/9
∴ The probability that sum of the numbers on the faces is 7 or 11 is 2∕9