AFCAT I 22 Jan 2025 Shift 2 Paper

Let the inner radius and outer radius be r cm and R cm respectively.
The width of the path will be (R−r)cm
Difference between the circumference of the outer and inner circle =144cm
‌⇒2πR−2πr=144
‌⇒2π(R−r)=144
‌⇒R−r=(144×7)∕44
‌⇒R−r=22.9≈23
∴ The width of the path is 23 cm .