AAI ATC Junior Executive 26 Dec 2015 Shift 2 Paper

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Question : 89 of 120

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The London equation in a super conductor is:

$∇^{2}B = B(mc^{2})\/ (4π \;\text " "\;nq^{2})$
$∇^{2}B = B(mc^{2})\/ (4π \;\text " "\;nq^{2})^{1\/ 2}.$
$∇^{2}B = B(mc^{2})\/ (4π \;\text " "\;nq^{2})^{2}.$
$∆ B = B(mc^{2})\/ (4π nq^{2})$

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