AAI ATC Junior Executive 26 Dec 2015 Shift 2 Paper

© examsiri.com

Question : 88 of 120

Marks: +1, -0

The magnetic field, due to a circular coil radius a, carrying a current I, at an axial point distance z from the centre of the coil, is given by:

$B = (µ _{0}ia^{2})\/ (2(a^{2} + z^{2})^{3\/ 2}).$
$B = (ia^{2})\/ (2(a^{2} + z^{2})^{3\/ 2}).$
$B = (µ _{0}ia^{2})\/ (2(a^{2} + z^{2}))$
$B = (µ _{0}ia^{2})\/ (a^{2} + z^{2})^{2}.$

Go to Question:

Prev Question

Next Question