ICSE Class 10 Physics 2022 Solved Paper

Question : 15 of 45

Marks: +1, -0

Calculate the thermal capacity of

40 {\g}

of water.
[Specific heat capacity of water

=4200

{\Jkg}^{-1}{ }^{∘} {\C}^{-1}]

Solution:

Given :

m=40 {\g}=\;{40}/{1000}=0.04 {\kg}

{\C}=4200 {\Jkg}^{-1}{ }^{∘} {\C}^{-1}

Thermal capacity

( {\C}^{'})

\;={\mass}(m) × \;\text " Specific heat capacity "\;( {\C})

\;=0.04 × 4200

\;=168 {\J}^{∘} {\C}^{-1}

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