50 {\g} of metal piece at 27^{\circ} {\C} requires 2400 {\J} of heat energy so as to attain a temperature of 327^{\circ} {\C}. Calculate the specific heat capacity of the metal.

ICSE Class 10 Physics 2014 Solved Paper - Question 28

Question : 28 of 66

Marks: +1, -0

50 {\g}

of metal piece at

27^{∘} {\C}

requires

2400 {\J}

of heat energy so as to attain a temperature of

327^{∘} {\C}

. Calculate the specific heat capacity of the metal.

Solution:

Given

\ m=50 {\g} ; ∆ t=327^{∘} {\C}-27^{∘} {\C}=300^{∘} {\C} \;\text ", "\;

{\Q}=2400 {\J} .

\;\;\text " Now, "\; \;\; {\Q}=m c ∆ t

\;2400=50 × c × 300

\;c=\;{2400}/{50 × 300}=0.16 {\J} \/ {\g}{ }^{∘} {\C} .

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