ICSE Class 10 Physics 2014 Solved Paper

Question : 27 of 66

Marks: +1, -0

Find the equivalent resistance between points

A

and

B

Solution:

\;\text " Let "\;\;\;{1}/{ {\R}_1}=\;{1}/{3}+\;{1}/{3}+\;{1}/{3}=\;{3}/{3}=1

∴ \;\; {\R}_1=1 Ω

{\R}_2\;=5 Ω

\;{1}/{ {\R}_3}\;=\;{1}/{4}+\;{1}/{6}=\;{3+2}/{12}=\;{5}/{12}

\; {\R}_3=\;{12}/{5}=2.4 Ω

Equivalent resistance between

{\A}

and

{\B}

R\;=R_1+R_2+R_3

\;=1+5+2 . 4=8.4 Ω .

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