CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 28 of 35
 
Marks: +1, -0
A series CR circuit with R=200 and C=(50π) µF is connected across an ac source of peak voltage ε0,=100V and frequency v=50Hz. Calculate (a) impedance of the circuit (Z),(b) phase angle (ϕ), and (c) voltage across the resistor.
Solution:
(a) Given, R=200,C=50πµF
Impedance: Z=R2+(1ωC)2
Or,
Z=(200)2+(12π×50×50π×106)2

Or,
Z=(200)2+(200)2
Z=2002
(b) Phase angle:
θ=tan11ωCR
or, θ=tan1(12π×50×50π×106×200)
or, θ=tan11
θ=45
(c) Voltage across resistor:
IRMS=εRMSZ
Or, IRMS=ε02Z
Or, IRMS =10022002
IRMS=14A
VR=IRMS ×R
Or, VR=14×200
VR=50V
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